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How do you differentiate # g(x) =4/x-cscx #?

Answer 1

Charles Anctil

#g'(x)=(4/x-cosecx)=-4/x^2+cosecx*cotx#

#d/dx(4/x-cosecx)=-4/x^2+cosecx*cotx#

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Answer 2

Aurora Alvarado

To differentiate ( g(x) = \frac{4}{x} - \csc(x) ), apply the quotient rule:

( g'(x) = \frac{d}{dx} \left(\frac{4}{x}\right) - \frac{d}{dx} \left(\csc(x)\right) )

( g'(x) = \frac{-4}{x^2} + \csc(x)\cot(x) )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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