# How do you differentiate #g(t)=1/(t^4+1)^3#?

To differentiate this function, you need to use the chain rule. When you do so, you get

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To differentiate ( g(t) = \frac{1}{(t^4 + 1)^3} ), you can use the chain rule. First, rewrite the function as ( g(t) = (t^4 + 1)^{-3} ). Then, differentiate using the chain rule:

[ g'(t) = -3(t^4 + 1)^{-4} \cdot 4t^3 ]

Simplify:

[ g'(t) = -12t^3(t^4 + 1)^{-4} ]

So, the derivative of ( g(t) ) with respect to ( t ) is ( -12t^3(t^4 + 1)^{-4} ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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