How do you differentiate #f(x)=x+x-2x# using the sum rule?

Answer 1

According to the sum rule,

#f'(x)=d/dx[x]+d/dx[x]-d/dx[2x]#
#d/dx[x]=1#
#d/dx[2x]=2#

Thus,

#f'(x)=1+1-2=color(red)(0#
This should be fairly obvious because #f(x)# can be simplified from the beginning to find that #f(x)=0#, so #f'(x)=0# as well.
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Answer 2

To differentiate ( f(x) = x + x - 2x ) using the sum rule, we apply the rule that states the derivative of the sum of two functions is the sum of their derivatives. In this case, we have three terms: ( x, x, ) and ( -2x ). The derivative of each term with respect to ( x ) is ( 1, 1, ) and ( -2 ), respectively. Therefore, the derivative of ( f(x) ) is the sum of these derivatives, which is ( 1 + 1 - 2 = 0 ). Thus, the derivative of ( f(x) ) is ( 0 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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