# How do you differentiate #f(x)=csc5x^5#?

we will need to use the chain rule;

let

By signing up, you agree to our Terms of Service and Privacy Policy

To differentiate the function f(x) = csc(5x^5), you can use the chain rule and the derivative of the cosecant function, which is -csc(x) * cot(x). Applying the chain rule, the derivative of csc(u) with respect to x is -csc(u) * cot(u) * du/dx.

So, for f(x) = csc(5x^5), the derivative is:

f'(x) = -csc(5x^5) * cot(5x^5) * d(5x^5)/dx

Now, find the derivative of 5x^5:

d(5x^5)/dx = 25x^4

Substitute this back into the expression:

f'(x) = -csc(5x^5) * cot(5x^5) * 25x^4

Therefore, the derivative of f(x) = csc(5x^5) is:

f'(x) = -25x^4 * csc(5x^5) * cot(5x^5)

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7