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How do you differentiate #f(x)=3secx(tanx)#?

Answer 1

Ezra Adams

#f'(x)=3secx(tan^2x+sec^2x)#

we need to use the product rule for this function

#f(x)=u(x)v(x)#

#=>f'(x)=v(x)color(red)(u'(x))+u(x)color(blue)(v'(x))#

so

#f(x)=3secxtanx#

#=>f'(x)=d/(dx)(3secxtanx)#

#f'(x)=3tanxcolor(red)(d/(dx)(secx))+3secxcolor(blue)(d/(dx)(tanx))#

#f'(x)=3tanxcolor(red)(secxtanx)+3secxcolor(blue)(sec^2x)#

#f'(x)=3secxtan^2x+3sec^3x#

#f'(x)=3secx(tan^2x+sec^2x)#

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Answer 2

Paisley Johnson

Paisley Johnson

To differentiate f(x) = 3sec(x)tan(x), you can use the product rule. The derivative is: f'(x) = 3sec(x)sec(x)tan(x) + 3sec(x)sec^2(x).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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