How do you differentiate #f(x) = 2x cos(x²)#?
Refer to explanation
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To differentiate the function f(x) = 2x cos(x²), you can use the product rule.
Let u(x) = 2x and v(x) = cos(x²). Then, differentiate both u(x) and v(x) separately.
u'(x) = 2 v'(x) = -2x sin(x²)
Now, apply the product rule:
f'(x) = u(x)v'(x) + v(x)u'(x)
f'(x) = (2x)(-2x sin(x²)) + cos(x²)(2)
Simplify:
f'(x) = -4x² sin(x²) + 2cos(x²)
So, the derivative of f(x) = 2x cos(x²) is f'(x) = -4x² sin(x²) + 2cos(x²).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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