# How do you differentiate #f(x)= -1 / (2x-7 )# using the quotient rule?

Eliminating the constant,

Using the chain rule

WE know,

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To differentiate ( f(x) = \frac{{-1}}{{2x - 7}} ) using the quotient rule, you would apply the formula ( \frac{{d}}{{dx}}\left(\frac{{f(x)}}{{g(x)}}\right) = \frac{{f'(x)g(x) - f(x)g'(x)}}{{[g(x)]^2}} ), where ( f(x) = -1 ) and ( g(x) = 2x - 7 ). Then, differentiate ( f(x) ) and ( g(x) ) separately and plug the results into the quotient rule formula.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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