# How do you differentiate #2y^2+2x^2=5#?

Use Implicit Differentiation:

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To differentiate the equation (2y^2 + 2x^2 = 5), you would differentiate each term with respect to the variables (x) and (y), separately.

(d/dx(2y^2) = 0), since (y) is independent of (x).

(d/dx(2x^2) = 4x).

Similarly, (d/dy(2y^2) = 4y) and (d/dy(2x^2) = 0).

So, the differentiation of (2y^2 + 2x^2 = 5) with respect to (x) is (4x) and with respect to (y) is (4y).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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