How do you differentiate #2=yln(e^(xy^3))+xe^(xy)#?
Using the Product and Sum/Difference Rule, we get,
This Answer is quite fair, but it can be put as :
Enjoy Maths.!
By signing up, you agree to our Terms of Service and Privacy Policy
To differentiate the given expression, apply the chain rule and the product rule:

Differentiate ( y \ln(e^{xy^3}) ): [ \frac{d}{dx}[y \ln(e^{xy^3})] = y \frac{d}{dx}[x  y^3] + \ln(e^{xy^3}) \frac{dy}{dx} ]

Differentiate ( x e^{xy} ): [ \frac{d}{dx}[x e^{xy}] = e^{xy} + x \frac{d}{dx}[e^{xy}] ]

Combine the results from steps 1 and 2 to find the overall derivative.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
 98% accuracy study help
 Covers math, physics, chemistry, biology, and more
 Stepbystep, indepth guides
 Readily available 24/7