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How do you determine the x and y intercepts of #y=-x^2-3x+18 #?

Answer 1

Eli Assouline

To find the #y#-intercept, we set #x=0#,

#y=-(0)^2-3(0)+18=18#

Hence, the #y#-intercept is #18#.

To find the #x#-intercepts, we set #y=0#,

#0=-x^2-3x+18#

by multiplying by #-1#,

#0=x^2+3x-18#

by factoring out,

#0=(x+6)(x-3) => x=-6,3#

Hence, the #x#-intercepts are #x=-6, 3#.

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Answer 2

Avery Alexander

To determine the x-intercepts, set y = 0 and solve for x. To find the y-intercept, set x = 0 and solve for y.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.