How do you determine the sum and product of the roots of #3x^2 + 2x = 0#?

Answer 1
Sum of the roots = #-2/3# and product 0.
Make the coefficient of #x^2# as 1 by dividing the equation by 3. #x^2# + #2/3# x +0=0

The negative of the coefficient of x, gives the sum of the roots, and the constant term 0, gives the product of the roots of the quadratic equation.

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Answer 2

To determine the sum and product of the roots of (3x^2 + 2x = 0), first, identify the coefficients of the quadratic equation, (a), (b), and (c). In this equation, (a = 3), (b = 2), and (c = 0). Then, use the formulas for sum and product of roots, which are given by:

Sum of roots, (S = -\frac{b}{a})

Product of roots, (P = \frac{c}{a})

Substitute the values of (a), (b), and (c) into these formulas to find the sum and product of the roots.

So,

Sum of roots, (S = -\frac{2}{3})

Product of roots, (P = \frac{0}{3} = 0)

Therefore, the sum of the roots is (-\frac{2}{3}) and the product of the roots is (0).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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