How do you determine the slope of the line passing through J(1, -4), K(3, -1)?

Answer 1

The slope of line JK is 3/2.

The slope formula is #(y_2-y_1)/(x_2-x_1)#, but I don't like formulas. There's almost always an easier way to remember this. In this case, it's "rise over run".

Rise is the change in the y-coordinates, and run is the change in the x-coordinates. You always put the 'y' on top so the slope makes "sense".

In this case, you can find the slope by thinking about this as a ratio of rise to run. You can see that the y-coordinate goes up 3 from J to K, and the x-coordinate goes up 2 from J to K, so the slope is the rise/run ratio 3/2.

Final Answer

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Answer 2

Ethan Adkins

To determine the slope of the line passing through two points, ( (x_1, y_1) ) and ( (x_2, y_2) ), you can use the formula:

[ \text{Slope} = \frac{y_2 - y_1}{x_2 - x_1} ]

In this case, the points are J(1, -4) and K(3, -1). Plugging these values into the formula:

[ \text{Slope} = \frac{-1 - (-4)}{3 - 1} = \frac{3}{2} ]

So, the slope of the line passing through J(1, -4) and K(3, -1) is ( \frac{3}{2} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.