How do you determine the molar mass of #Fe_2O_3#?
First, you want to have a periodic table available so you can determine the atomic weight of Fe and O:
From the chemical formula, we have 2 iron atoms. You have to multiply the atomic mass of Fe by 2 to ascertain an atomic weight of 111.7 g/mol
Next, you have 3 oxygen atoms, so you would multiply the atomic mass of O by 3 to obtain an atomic weight of 48.00 g/mol
Now you want to add the mass of each atom together to obtain the molar mass of the entire compound:
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To determine the molar mass of Fe2O3, you calculate the sum of the atomic masses of the atoms in the compound. For Fe2O3:
Fe: atomic mass = 55.845 g/mol (for one Fe atom) O: atomic mass = 16.00 g/mol (for one O atom)
Multiply the atomic mass of Fe by 2 (because there are 2 Fe atoms) and the atomic mass of O by 3 (because there are 3 O atoms), then sum the results:
Molar mass of Fe2O3 = (2 * 55.845 g/mol) + (3 * 16.00 g/mol) = 111.69 g/mol + 48.00 g/mol = 159.69 g/mol
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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