How do you determine the limit of #(8/x^3) + 8# as x approaches 0+?
which proves the point.
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To determine the limit of (8/x^3) + 8 as x approaches 0+, we substitute 0 into the expression. This gives us (8/0^3) + 8, which simplifies to (8/0) + 8. Since division by zero is undefined, the limit does not exist.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- How do you evaluate the limit #(x^3+27)/(x+3)# as x approaches #3#?
- How do you find the Limit of #lnx# as x approaches 0?
- How do you evaluate the limit #(x-1)/(x^2-1)# as x approaches #1#?

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