# How do you determine the convergence or divergence of #Sigma sin(((2n-1)pi)/2)# from #[1,oo)#?

Not convergent.

Finally

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To determine the convergence or divergence of the series Σ sin(((2n-1)π)/2) from n = 1 to infinity, you can apply the divergence test. The series diverges because the sequence sin(((2n-1)π)/2) does not approach zero as n approaches infinity.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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