How do you determine if the improper integral converges or diverges #e^(-2t) dt # from negative infinity to -1?
The integral is divergent
The improper ntegral is
Therefore,
The integral is divergent
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To determine if the improper integral ( \int_{-\infty}^{-1} e^{-2t} , dt ) converges or diverges, we evaluate the integral by finding its antiderivative and then applying the limits of integration.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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