# How do you determine if #f(x)=7x^2 - 2x + 1# is an even or odd function?

neither

Take into account the following when determining whether a function is even or odd.

• f(x) is even if f(x) = f( -x)

About the y-axis, even functions are symmetrical.

• f(x) is odd if f(-x) = - f(x).

There is symmetry around the origin of odd functions.

Check for even

f(x) is not even since f(x) ≠ f(-x)

Check for odd

f(x) is not odd since f(-x) ≠ - f(x) graph{7x^2-2x+1 [-10, 10, -5, 5]}.

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To determine if a function ( f(x) = 7x^2 - 2x + 1 ) is even or odd, you need to check its symmetry properties.

- Even functions satisfy the condition ( f(x) = f(-x) ) for all ( x ) in their domain.
- Odd functions satisfy the condition ( f(x) = -f(-x) ) for all ( x ) in their domain.

For ( f(x) = 7x^2 - 2x + 1 ):

- Substitute ( -x ) into the function: ( f(-x) = 7(-x)^2 - 2(-x) + 1 = 7x^2 + 2x + 1 ).
- Compare ( f(x) ) with ( f(-x) ):
- If ( f(x) = f(-x) ), the function is even.
- If ( f(x) = -f(-x) ), the function is odd.

In this case: ( f(x) \neq f(-x) ) and ( f(x) \neq -f(-x) ).

Therefore, ( f(x) = 7x^2 - 2x + 1 ) is neither even nor odd.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How do you determine if #f(x) = x^3 - x^5# is an even or odd function?
- What transformation can you apply to #y=sqrtx# to obtain the graph #y=sqrt(-2x)-8#?

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