How do you convert the parametric equations into a Cartesian equation by eliminating the parameter r: #x=(r^2)+r#, #y=(r^2)-r#?

Answer 1

# x^2+y^2 -2x-2y -2xy = 0 #

We have:

# x=r^2 + r # # y=r^2 - r #

Adding the equations:

# x+ y = 2r^2 => r^2 = 1/2(x+y) #

Multiplying the Equations we get:

# xy = (r^2 + r)(r^2 - r) # # \ \ \ \ = r^4 - r^2 #
And substituting #r^2 = 1/2(x+y) # gives:
# xy = (1/2(x+y))^2 - 1/2(x+y) #

Thus the Cartesian equation is:

# xy = 1/4(x+y)^2 - 1/2(x+y) # # 4xy = (x^2+2xy+y^2) -2(x+y) # # 4xy = x^2+2xy+y^2 -2x-2y # # x^2+y^2 -2x-2y -2xy = 0 #
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Answer 2

#x^2+y^2-2xy-2x-2y = 0#

We have:

#{(x=r^2+r),(y=r^2-r):}#

Summing the equations we have:

#x+y = 2r^2#

and subtracting the second from the first:

#x-y = 2r#

or:

#r=(x-y)/2#

Then:

#x+y = 2((x-y)/2)^2#
#x+y = (x-y)^2/2#
#2x+2y = x^2-2xy+y^2#

and finally:

#x^2+y^2-2xy-2x-2y = 0#

This is the equation of a conic, so we can calculate the invariants:

#det ((1,-1,-1),(-1,1,-1),(-1,-1,0)) = -4#

The cubic invariant is non null so the conic is non-degenerate,

#det( ( 1,-1),(-1,1)) = 0#

the quadratic invariant is null so the conic is a parabola.

graph{x^2+y^2-2xy-2x-2y=0 [-213.9, 213.8, -106.2, 107.5]}

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Answer 3

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  1. From the first equation ( x = r^2 + r ), solve for ( r ):

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  1. From the first equation ( x = r^2 + r ), solve for ( r ):

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  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expressionTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

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[ r^2 + r - x = 0 ]

Using the quadratic formula:

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  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression forTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

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First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-bTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( rTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pmTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r )To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) intoTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrtTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into theTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the secondTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{bTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equationTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

whereTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation (To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where (To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( yTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a =To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - rTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y =To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ),To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), (To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \leftTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( bTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left(To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b =To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \fracTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ),To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 +To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), andTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and (To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrtTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( cTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c =To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2}To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ rTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r =To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \rightTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \fracTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 -To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

SubTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

SubstituteTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute (To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 +To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( rTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r )To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 +To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( yTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y =To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = rTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4xTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{2To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r ):

[To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{2}To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r ):

[ yTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{2} \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r ):

[ y =To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{2} ]

To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r ):

[ y = \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{2} ]

3To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r ):

[ y = \left(To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{2} ]

3.To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r ):

[ y = \left( \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. SimplTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r ):

[ y = \left( \fracTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. SimplifyTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r ):

[ y = \left( \frac{-To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Simplify thisTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r ):

[ y = \left( \frac{-1 \pm \sqrt{1 + 4x}}{2} \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Simplify this equation toTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r ):

[ y = \left( \frac{-1 \pm \sqrt{1 + 4x}}{2} \rightTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Simplify this equation to getTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r ):

[ y = \left( \frac{-1 \pm \sqrt{1 + 4x}}{2} \right)^To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Simplify this equation to get theTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r ):

[ y = \left( \frac{-1 \pm \sqrt{1 + 4x}}{2} \right)^2To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Simplify this equation to get the CartesianTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r ):

[ y = \left( \frac{-1 \pm \sqrt{1 + 4x}}{2} \right)^2 -To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Simplify this equation to get the Cartesian equationTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r ):

[ y = \left( \frac{-1 \pm \sqrt{1 + 4x}}{2} \right)^2 - \To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Simplify this equation to get the Cartesian equation.To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r ):

[ y = \left( \frac{-1 \pm \sqrt{1 + 4x}}{2} \right)^2 - \leftTo eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve for ( r ) in one equation and substitute it into the other equation.

  1. From the first equation ( x = r^2 + r ), solve for ( r ):

[ r = \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Substitute this expression for ( r ) into the second equation ( y = r^2 - r ):

[ y = \left( \frac{-1 + \sqrt{1 + 4x}}{2} \right)^2 - \frac{-1 + \sqrt{1 + 4x}}{2} ]

  1. Simplify this equation to get the Cartesian equation.To eliminate the parameter ( r ) and convert the parametric equations ( x = r^2 + r ) and ( y = r^2 - r ) into a Cartesian equation, you can solve one equation for ( r ) and then substitute it into the other equation.

First, solve ( x = r^2 + r ) for ( r ):

[ r^2 + r - x = 0 ]

Using the quadratic formula:

[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

where ( a = 1 ), ( b = 1 ), and ( c = -x ), you get:

[ r = \frac{-1 \pm \sqrt{1 + 4x}}{2} ]

Substitute ( r ) into ( y = r^2 - r ):

[ y = \left( \frac{-1 \pm \sqrt{1 + 4x}}{2} \right)^2 - \left( \frac{-1 \pm \sqrt{1 + 4x}}{2} \right) ]

After simplification, you will obtain the Cartesian equation in terms of ( x ) and ( y ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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