How do you convert the following? A)0.56 mol C6H6 to molecules C6H6 B) 4.25x10^-4 mol to H2SO4 to grams

Answer 1

a. #3.3712*10^(23)#

b. #0.04165g#

a. #a=nL#, where: - #n# = number of moles (#mol#) - #L# = Avogradro's constant (#~~6.02*10^(23)# #mol^(-1)#) - #a# = number of molcules/ions/atoms

#a=(6.02*10^(23))(0.56)=3.3712*10^(23)#

b. #m/M=n#, where:

#m=Mn=(4.25*10^(-4))(2(1)+32+4(16))=0.04165g#

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Answer 2

Jeremiah Adams

A) To convert 0.56 mol of C6H6 to molecules of C6H6: [0.56 \text{ mol} \times 6.022 \times 10^{23} \text{ molecules/mol} = 3.37 \times 10^{23} \text{ molecules of } C_6H_6]

B) To convert 4.25x10^-4 mol of H2SO4 to grams: [4.25 \times 10^{-4} \text{ mol} \times 98.079 \text{ g/mol} = 0.0412 \text{ grams of } H_2SO_4]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.