# How do you convert r = -2cos(θ) – 2sin(θ) into cartesian mode?

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To convert the polar equation ( r = -2\cos(\theta) - 2\sin(\theta) ) into Cartesian mode, use the trigonometric identities ( x = r\cos(\theta) ) and ( y = r\sin(\theta) ). Substitute these into the equation and simplify to obtain the Cartesian equation.

( r = -2\cos(\theta) - 2\sin(\theta) )

( x = -2\cos(\theta) )

( y = -2\sin(\theta) )

( x = -2x )

( y = -2y )

( x^2 + y^2 = 4(x^2 + y^2) )

( 3x^2 + 3y^2 = 0 )

( x^2 + y^2 = 0 )

( x = 0 ) and ( y = 0 )

The Cartesian equation of the polar equation ( r = -2\cos(\theta) - 2\sin(\theta) ) is ( x^2 + y^2 = 0 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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