# How do you convert #r^2=cos(theta)# to polar form?

It *is* in polar form. If you meant converting to rectangular form, that would be

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To convert ( r^2 = \cos(\theta) ) to polar form, you need to express it in terms of ( r ) and ( \theta ). Since ( r^2 = x^2 + y^2 ) in polar coordinates, where ( x = r \cos(\theta) ) and ( y = r \sin(\theta) ), you can substitute these expressions into ( r^2 = \cos(\theta) ). After substitution and simplification, you'll get ( r = \sqrt{\cos(\theta)} ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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