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How do you convert #r^2=cos(theta)# to polar form?

Answer 1

Delilah Aguilar

It is in polar form. If you meant converting to rectangular form, that would be #(x^2+y^2)^{3/2}=x#.

Multiply by #r# to get

#r^3=r\cos(\theta)#.

Then put in #r=(x^2+y^2)^{1/2}#, #r\cos(\theta)=x#.

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Answer 2

Anna Andrews

To convert ( r^2 = \cos(\theta) ) to polar form, you need to express it in terms of ( r ) and ( \theta ). Since ( r^2 = x^2 + y^2 ) in polar coordinates, where ( x = r \cos(\theta) ) and ( y = r \sin(\theta) ), you can substitute these expressions into ( r^2 = \cos(\theta) ). After substitution and simplification, you'll get ( r = \sqrt{\cos(\theta)} ).

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