# How do you convert #r - 2 cos t = 3 sin t# to rectangular form?

graph{x^2+y^2-2x-3y=0 [-4.313, 5.69, -1.38, 3.62]}

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To convert ( r - 2 \cos(t) = 3 \sin(t) ) to rectangular form, we use the relationships between polar and rectangular coordinates:

( x = r \cos(t) ) ( y = r \sin(t) )

Substitute these relationships into the given polar equation:

( r - 2 \cos(t) = 3 \sin(t) )

( x - 2x = 3y )

( x - 3y = 0 )

This is the rectangular form of the polar equation.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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