How do you convert Hubble's constant?

Question

Christopher Ales · Accepted Answer

The Hubble's constant #H_0# is 71 km/sec/mega parsec, nearly. See explanation for conversion.

#H_0# km/sec/mega parsec #=H_0 X 10^(-6)# km/sec/parsec #=(H_0 X 10^(-6)/206265)=4.85 x 10^(-12)H_0# km/sec/AU #=(((H_0 X 10^(-6)/206265))/149597871)= 3.24 X 10^(-20)H_0# km/sec/km #=(((H_0 X 10^(-6)/206265))/149597871)(365.25 X 24 X 3600)# #=1.02 X 10^(-12)H_0# km/year/km In this second edition, i convert #H_0 to age of our universe, in the Hubble path. The age of our universe is #1/H_0# years, where #H_0# is obtained at your discretion, in u/year/u, with u representing a distance unit. This invariant factor to be applied to the standard #H_0= 71# km/sec/parsec is #1.02 X 10^(-12)# Now, #1/(converted H_0)# #=1/(71 X 1.02 X 10^(-12)) = 1.38 X 10^10# years. #=13.8# billion years.

Ivy Allen · Answer

undefined Hubble's constant can be expressed in kilometers per second per megaparsec (km/s/Mpc). Conversion factors or dimensional analysis can be used to convert Hubble's constant to another unit. For example, multiplying by 1,000 will convert km/s/Mpc to km/s/pc, since there are 1,000 parsecs in a megaparsec.