How do you convert 64.1 g of aluminum to moles?

Answer 1

Well what is the molar mass of aluminum metal?

Your Periodic Table will tell you that it is #27.0*g*mol^-1#...
And so we take the quotient...#(64.1*g)/(27.0*g*mol^-1)=2.37*mol#

What is the number of aluminum atoms in this molar quantity?

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Answer 2

An aluminum mole is equal to 27 g (\frac{64.1 , \text{g}}{27 , \text{g/mol}} = 2.374 , \text{mol} )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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