How do you convert 25g #Fe_2O_3# to moles?

Question

Jeremiah Adams · Accepted Answer

Divide the mass by the molar mass to get a molar quantity.

#(25*g)/(159.69*g*mol^-1)=??mol#

Cooper Adams · Answer

undefined Use the molar mass of Fe2O3, which is roughly 159.69 g/mol, to convert 25g of Fe2O3 to moles. Then, divide the given mass (25g) by the molar mass: $ \text{Number of moles} = \frac{25 \text{g}}{159.69 \text{ g/mol}} $ This yields about 0.157 moles of Fe2O3.

Luna Chen · Answer

undefined To convert 25 grams of $ \text{Fe}_2\text{O}_3 $ to moles, we need to use the molar mass of $ \text{Fe}_2\text{O}_3 $, which is the sum of the atomic masses of its constituent elements.

The molar mass of iron (Fe) is approximately 55.845 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol.

Since there are 2 atoms of iron and 3 atoms of oxygen in $ \text{Fe}_2\text{O}_3 $, we calculate its molar mass as follows:

$$ \text{Molar mass of } \text{Fe}_2\text{O}_3 = (2 \times \text{Molar mass of Fe}) + (3 \times \text{Molar mass of O}) $$
$$ = (2 \times 55.845 \text{ g/mol}) + (3 \times 16.00 \text{ g/mol}) $$
$$ = 111.69 \text{ g/mol} + 48.00 \text{ g/mol} $$
$$ = 159.69 \text{ g/mol} $$

Now, to convert 25 grams of $ \text{Fe}_2\text{O}_3 $ to moles, we use the formula:

$$ \text{moles} = \frac{\text{mass}}{\text{molar mass}} $$

Substituting the given mass and molar mass:

$$ \text{moles} = \frac{25 \text{ g}}{159.69 \text{ g/mol}} $$
$$ \text{moles} \approx 0.1567 \text{ mol} $$

Therefore, 25 grams of $ \text{Fe}_2\text{O}_3 $ is approximately 0.1567 moles.