How do you convert #(2,(-7pi)/6)# into cartesian form?

Answer 1

Use #x=rcostheta# and #y=rsintheta#. Answer: #(-sqrt(3),1)#

Original problem: Convert #(2, -(7pi)/6)# to Cartesian
To convert from polar coordinates to Cartesian form, we use the equations #x=rcostheta# and #y=rsintheta#.
Since we have #(r,theta)#, we can simply substitute into the above formulas: #x=2cos(-(7pi)/6)# Using our unit circle trig values #x=2(-sqrt(3)/2)# #x=-sqrt(3)#
#y=2sin(-(7pi)/6)# Using our unit circle trig values #y=2(1/2)# #y=1#
Therefore our final answer in Cartesian form is: #(-sqrt(3),1)#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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