How do you convert # (-2, 2sqrt3)# to polar form?

Answer 1

In Polar form #(r,theta)# is #4,120^0#

Polar distance #r=sqrt((-2)^2+(2sqrt3)^2)=4# #theta=tan^-1((2sqrt3)/-2)=tan^-1(- sqrt3) =120^0# since the point is on 2nd quadrant [Ans]
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Answer 2

To convert the point (-2, 2√3) to polar form:

  1. Calculate the magnitude (r) using the formula: r = √(x^2 + y^2), where x is the x-coordinate (-2) and y is the y-coordinate (2√3).
  2. Determine the angle (θ) using the formula: θ = arctan(y/x), where y is the y-coordinate (2√3) and x is the x-coordinate (-2).
  3. Express the point in polar form as (r, θ).
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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