How do you convert 15.0 g to #C_2H_6#?

Question

Naomi Aronson · Accepted Answer

I think you mean how do you convert a mass of #15*g# of ethane to moles of ethane.

#"Moles of ethane"# #=# #(15.0*cancelg)/(30.07*cancelg*mol^-1)=??mol#. And thus a mass of #15*g# of ethane represents #1/2# a mole of ethane. How many ethane molecules are there in such a molar quantity?

Xavier Avery · Answer

undefined You must use the molar mass of ethane in order to convert 15.0 g to C2H6 (ethane). The molar mass of C2H6 is approximately 30.07 g/mol. Using this information, you can calculate the number of moles in 15.0 g of C2H6 as follows: $$ \text{moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{15.0 \text{ g}}{30.07 \text{ g/mol}} \approx 0.498 \text{ mol} $$.

Owen Ambrose · Answer

undefined To convert grams of a substance to moles, you need to divide the given mass by the molar mass of the substance. The molar mass of $ C_2H_6 $ (ethane) can be calculated by adding the molar masses of the constituent elements:

$$
\text{Molar mass of } C_2H_6 = (2 \times \text{molar mass of C}) + (6 \times \text{molar mass of H})
$$

Using the atomic masses from the periodic table:

- Molar mass of carbon (C) = 12.01 g/mol
- Molar mass of hydrogen (H) = 1.008 g/mol

Now, calculate the molar mass of $ C_2H_6 $:
$$ (2 \times 12.01 \, \text{g/mol}) + (6 \times 1.008 \, \text{g/mol}) = 24.02 \, \text{g/mol} + 6.048 \, \text{g/mol} = 30.068 \, \text{g/mol} $$

To convert 15.0 g of $ C_2H_6 $ to moles, use the formula:
$$ \text{moles} = \frac{\text{mass}}{\text{molar mass}} $$

$$ \text{moles} = \frac{15.0 \, \text{g}}{30.068 \, \text{g/mol}} $$

$$ \text{moles} = 0.4988 \, \text{mol} $$

So, 15.0 grams of $ C_2H_6 $ is equivalent to approximately 0.4988 moles.