How do you convert 0.219 (19 repeating) to a fraction?

Answer 1

#217/990#

There is a technique for changing recurring decimals to fractions.

Let #x = 0.21919191919....... # to infinity
#10x = 2.19191919191919...#to infinity.
#1000x = 219.1919191919 # to infinity
Do you see what will happen if we subtract #1000x -10x?#
#1000x = 219.1919191919 # to infinity #ul(-10x)" " ul(-2.19191919191919...)#to infinity. #990x = 217.0000000000000...# to infinity
Solve for #x#
#x = 217/990#

Notice the following:

Not all the decimals recur. The recurring starts after 3 decimal places. This was the reason for multiplying by #1000#. The digits must line up so that when you subtract there will be zero's to infinity.

This method can be summarised as follows:

#x = (219-2)990 = 217/990#
#291: " " # write down all the digits until they start to recur. #-2: " "#subtract the digits that do NOT recur
#div 990:" "# divide by a 9 for each recurring digit followed by a 0 for each non-recurring digit.
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Answer 2

To convert the repeating decimal 0.219 (19 repeating) to a fraction, we can represent it as ( \frac{219}{1000} ) and simplify it to ( \frac{219}{999} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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