How do you compute (fog) and (gof) if #f(x) = (3x-1) / (2x+5)# and #g(x) =(7x+3) / (3x-1)#?
To compute (fog) and (gof), first find the compositions f(g(x)) and g(f(x)).
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To find (fog), substitute g(x) into f(x). So, (fog)(x) = f(g(x)). (fog)(x) = f(g(x)) = f((7x+3)/(3x-1)) = [3(7x+3) - 1] / [2(7x+3) + 5]
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To find (gof), substitute f(x) into g(x). So, (gof)(x) = g(f(x)). (gof)(x) = g(f(x)) = g((3x-1)/(2x+5)) = [7(3x-1) + 3] / [3(3x-1) - 1]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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