# How do you complete the square to solve #x^2 - 8x + 13 = 0#?

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To solve x^2 - 8x + 13 = 0 by completing the square:

- Move the constant term to the right side: x^2 - 8x = -13
- Halve the coefficient of x (-8/2 = -4) and square it (-4^2 = 16).
- Add this squared value to both sides of the equation: x^2 - 8x + 16 = -13 + 16
- Factor the perfect square trinomial: (x - 4)^2 = 3
- Take the square root of both sides: x - 4 = ±√3
- Solve for x: x = 4 ± √3

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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