How do you complete the square to solve #x^2 + 6x + 34 = 0#?
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To solve the equation x^2 + 6x + 34 = 0 by completing the square:
- Move the constant term to the other side of the equation: x^2 + 6x = -34.
- To complete the square, take half of the coefficient of x (6/2 = 3), square it (3^2 = 9), and add it to both sides of the equation: x^2 + 6x + 9 = -34 + 9.
- Simplify: (x + 3)^2 = -25.
- Take the square root of both sides: x + 3 = ±√(-25).
- Simplify: x + 3 = ±5i.
- Subtract 3 from both sides: x = -3 ± 5i.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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