How do you complete the square to solve #0=5x^2 + 2x - 3#?
Put your equation in standard form in step 1.
Step 2: Shift the constant to the equation's right side.
Each of the two sides is divided by 5.
Step 4: Divide by 4 after squareing the coefficient of x.
Step 5: Increase the outcome on both sides.
Step 6: Calculate each side's square root.
Case 1
Case 2
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To solve the quadratic equation 0 = 5x^2 + 2x - 3 by completing the square, follow these steps:
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Move the constant term to the other side of the equation: 5x^2 + 2x = 3
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Divide the coefficient of the x^2 term by 2, square the result, and add it to both sides of the equation: 5x^2 + 2x + (2/2)^2 = 3 + (2/2)^2 5x^2 + 2x + 1 = 3 + 1
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Factor the left side of the equation as a perfect square: (sqrt(5)x + 1)^2 = 4
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Take the square root of both sides to solve for x: sqrt((sqrt(5)x + 1)^2) = ±sqrt(4) sqrt(5)x + 1 = ±2
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Subtract 1 from both sides: sqrt(5)x = -1 ± 2
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Solve for x: x = (-1 ± 2)/sqrt(5)
Therefore, the solutions to the equation 0 = 5x^2 + 2x - 3 by completing the square are: x = (-1 + 2)/sqrt(5) or x = (-1 - 2)/sqrt(5)
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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