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How do you complete each ordered pair (_, 11) so that it is a solution to 6x - y = 7?

Answer 1

#(underlinecolor(red)3,11)# is a solution to #6x-y=7#

Note I have used the letter #a# in place of the underscore from the original version of the question. ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ If #(color(red)x,color(blue)(y))=(color(red)a,color(blue)(11))# is a solution to #6color(red)x-color(blue)y = 7# then #color(white)("XXX")6color(red)a-color(blue)(11)=7# #rarr# #color(white)("XXX")6color(red)a=18# #rarr# #color(white)("XXX")color(red)a=3#

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Answer 2

Isaiah Anthony

To complete each ordered pair (_, 11) so that it is a solution to 6x - y = 7, you need to solve for the missing value of x by substituting y = 11 into the equation and solving for x.

6x - 11 = 7 6x = 18 x = 3

So, the completed ordered pairs are (3, 11).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.