How do you compare each pair of fractions with <, > or = given #3/4, 8/12#?

Answer 1

Make the denominators the same and then compare

The first step to solving this problem would be to make the denominators the same:

#4 xx 3 = 12#, so multiply both halves the first fraction by 3: #3 xx 3 = 9#, and #4 xx 3 = 12#. You now have the fractions #9/12# and #8/12#.

The second step is to compare the numerators: is 9 greater than, (#>#) equal to (#=#), or less than (#<#) 8? Clearly, 9 is greater than 8, so #9/12> 8/12#.

Therefore, your answer (using the original fractions) would be: #3/4 >8/12#

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Answer 2

Levi Adams

To compare the fractions ( \frac{3}{4} ) and ( \frac{8}{12} ), first, we need to make their denominators the same:

( \frac{3}{4} = \frac{3}{4} ) (already in simplest form)

( \frac{8}{12} = \frac{2}{3} ) (simplified by dividing numerator and denominator by 4)

Now, we can see that ( \frac{3}{4} ) is less than ( \frac{2}{3} ), because when fractions have the same denominator, the one with the smaller numerator is smaller overall.

So, ( \frac{3}{4} < \frac{8}{12} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you compare each pair of fractions with &lt;, &gt; or = given #3/4, 8/12#?

How do you compare each pair of fractions with <, > or = given #3/4, 8/12#?