# How do you combine #n/(5-n)+(2n-5)/(n-5)#?

Using an example. Suppose we had -5

So we can 'force' a change in sign so that both denominators are the same:

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To combine the expressions n/(5-n) and (2n-5)/(n-5), we need to find a common denominator. The common denominator in this case is (5-n)(n-5).

Next, we can rewrite the fractions with the common denominator:

n/(5-n) = -n/(n-5) (2n-5)/(n-5) = (2n-5)/(n-5)

Now, we can add the fractions together:

-n/(n-5) + (2n-5)/(n-5) = (-n + 2n - 5)/(n-5) = (n - 5)/(n-5)

Simplifying further, we have:

(n - 5)/(n-5) = 1

Therefore, the combined expression simplifies to 1.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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