How do you combine #(2x^2 - 6x - 2) + (x* + 4x) + ( 3x^2 + x + 5)?#?

Answer 1

#6x^2 - x +3#

Combine    #(2x^2−6x−2)+(color(red)(x⋅)+4x)+(3x^2+x+5)#
NOTE: I think this part #rarr# #color(red)(x⋅)# #larr#is a typo for #color(red)(x^2)#
So I will write the problem this way: Combine    #(2x^2−6x−2)+(color(red)(x^2)+4x)+(3x^2+x+5)#
  1. Clear the parentheses by distributing their coefficients
In this case, the coefficients are #1#s, which are not written because they are understood. But you can always just pencil them in for yourself, like this:
#color(lightgray)1(2x^2−6x−2)+color(lightgray)1(x^2+4x)+color(lightgray)1(3x^2+x+5)#
  1. Clear the parentheses by distributing the coefficients After you have distributed, you will get this:
#2x^2−6x−2+x^2+4x+3x^2+x+5#
  1. Group like terms to make it easier to combine them
#2x^2+x^2+3x^2    −6x+4x+x      −2+5#
  1. Combine like terms
#6x^2 - x +3# #larr# answer
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Answer 2

Combine the terms by adding like terms together:

[ (2x^2 - 6x - 2) + (x^2 + 4x) + (3x^2 + x + 5) = 2x^2 - 6x - 2 + x^2 + 4x + 3x^2 + x + 5 ]

[ = (2x^2 + x^2 + 3x^2) + (-6x + 4x + x) + (-2 + 5) ]

[ = 6x^2 - x + 3 ]

So, the combined expression is ( 6x^2 - x + 3 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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