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How do you calculate the surface area of the lateral faces of a regular hexagonal pyramid that has a slant height of 35 cm and a base side length of 4 cm?

Answer 1

Area of the lateral faces of the pyramid: #420 cm^2#

A hexagonal pyramid has 6 faces, all triangles.

A slant height of a pyramid is the height of a triangle or face of the pyramid. If the pyramid is regular. all slant heights are equal.

So it's only necessary to find the area of one face of the pyramid and multiply it by 6:

#S_"lateral faces of pyramid"= 6*S_(face)=6*(base*height)/2=3*base*"slant face"=3*4*35=420 cm^2#

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Answer 2

Wyatt Anderson

To calculate the surface area of the lateral faces of a regular hexagonal pyramid, you need to use the formula:

Surface Area = 6 * (1/2) * base side length * slant height

Plug in the given values:

Surface Area = 6 * (1/2) * 4 cm * 35 cm

Surface Area = 6 * 2 cm * 35 cm

Surface Area = 12 cm * 35 cm

Surface Area = 420 cm²

So, the surface area of the lateral faces of the regular hexagonal pyramid is 420 square centimeters.

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Answer from HIX Tutor

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