How do you calculate the pOH of HCl?

Answer 1

#pOH=14-pH#

You can simply find the #pH# from the concentration of #H^(+)# which is equal to:

#[H^(+)]=[HCl]_0#

Then, #pH=-log[H^(+)]#

From the water dissociation constant #k_w=[H^(+)][OH^(-)]=1.0xx10^(-14)# we can take the #-log# of both parties, we get:

#-logk_w=-log[H^(+)]-log[OH^(-)]=14#

knowing that #pH=-log[H^(+)]# and #pOH=-log[OH^(-)]#, therefore,

#pH+pOH=14=>pOH=14-pH#

Here is a video that further explains this topic:
Acids & Bases | Nature, Strength & pH Scale.

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Answer 2

Natalie Anton

The pOH of a solution can be calculated using the negative logarithm of the hydroxide ion concentration ([OH^-]). In the case of HCl, which is a strong acid that completely dissociates in water, the concentration of hydroxide ions is negligible. Therefore, the pOH of HCl is effectively 0.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.