How do you calculate the percentage composition of Oxygen in #N_2O_5#?

Question

Natalie Anton · Accepted Answer

#25.93%# #N#, #74.07%##O#

You first need refrence a periodic table to find the weight of #N# and #O#

#N# = #14.0g# #O# = #16.0g#

Multiply each element based on how many of each element are in the compound. for #N#, it is 2. For #O#, it is 5.

#14.0g# #O# * 2 = #28.0g# #N#

#16.0g# #O# * 5 = #80.0g# #O#

add the two weights together to get the total weight of #N_2O_5#

#28.0g# + #80.0g# = #108g# #N_2O_5#

The percentage composition can be obtained by dividing the weight of each element by the compound's total weight and multiplying the result by 100.

#(28.0gN)/(108g)# * 100 = #25.93%# #N#

#(80.0gO)/(108g)# * 100 = #74.07%# #O#

Natalie Anton · Answer

undefined Determine the molar masses of oxygen (O) and nitrogen (N) in N3O₅. Calculate the relative contributions of each element to the molar masses. To obtain the percentage composition, divide the molar mass of oxygen by the molar mass of N3O₅ and multiply the result by 100.