How do you calculate the percent composition of all the elements in #Ca(NO_3)_2#?

Question

Wyatt Adkins · Accepted Answer

Well, take the weighted mass of each element as a percentage of the molecular mass....

And calcium nitrate has a molar mass of #164.09* g*mol^-1#.. ...and thus #%Ca=(40.1*g)/(164.09*g*mol^-1)xx100%=24.4%# ...and #%N=(2xx14.01*g)/(164.09*g*mol^-1)xx100%=17.1%# ...and #%O=(6xx16.00*g)/(164.09*g*mol^-1)xx100%=58.5%# Do the percentages add up to #100%#? Should they do so?

Peyton Adams · Answer

undefined To calculate the percent composition of each element in Ca(NO3)2, you need to determine the molar mass of the compound, then divide the molar mass of each individual element by the total molar mass of the compound and multiply by 100 to get the percentage.

1. Calculate the molar mass of Ca(NO3)2:
   Ca: 1 * 40.08 g/mol = 40.08 g/mol
   N: 2 * 14.01 g/mol = 28.02 g/mol
   O: 6 * 16.00 g/mol = 96.00 g/mol
   Total molar mass = 40.08 + 28.02 + 96.00 = 164.10 g/mol

2. Calculate the percent composition of each element:
   Calcium (Ca): (40.08 g/mol / 164.10 g/mol) * 100 = 24.44%
   Nitrogen (N): (28.02 g/mol / 164.10 g/mol) * 100 = 17.06%
   Oxygen (O): (96.00 g/mol / 164.10 g/mol) * 100 = 58.50%

Therefore, the percent composition of each element in Ca(NO3)2 is:
- Calcium (Ca): 24.44%
- Nitr