How do you calculate the number of moles of potassium hydroxide that must be dissolved to make the following solution: 500 #cm^3# of 1 #mol##/##dm^3#?

Answer 1

We use the relationship, #"Concentration"# #=# #"Moles of solute"/"Volume of solution"#. #0.500*mol# #KOH# are required.

We are given that #"Concentration"# #=# #1*mol*dm^-3#, and that the volume of this solution is #500*cm^3# #=# #0.500*dm^3#.

Thus #"moles of solute"# #=# #"concentration "xx" volume"# #=# #1*mol*cancel(dm^-3)xx0.500*cancel(dm^3)# #=# #0.500*mol#.

What is the mass of the #KOH# used here?

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Answer 2

Peyton Adams

Number of moles = concentration × volume Number of moles of potassium hydroxide = (1 mol/dm^3) × (500 cm^3 / 1000 cm^3) Number of moles of potassium hydroxide = 0.5 moles

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.