How do you calculate the molarity of each solution 1.0 mol KCI in 750 mL of solution and then 0.50 mol #MgCl_2# in 1.5 L of solution?

Answer 1

With ease.........we use the quotient...

#"Molarity"="Moles of solute"/"Volume of solution"#

And thus #[KCl]=(1.0*mol)/(0.750*L)=1.33*mol*L^-1#.

And #[MgCl_2]=(0.50*mol)/(1.50*L)=0.33*mol*L^-1#.

I include the units because, by using the provided units, it is fairly simple to determine when to divide and when to multiply when calculating a volume or the moles of solute present.

What is the chloride ion concentration in each solution?

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Answer 2

Wyatt Adkins

The molarity of the 1.0 mol KCl solution in 750 mL of solution is 1.33 M, and the molarity of the 0.50 mol MgCl2 solution in 1.5 L of solution is 0.33 M.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.