Home > Chemistry > Solution Formation

How do you calculate the mass of HCI required to prepare 2.5 liters of a 0.08 molar solution of HCI?

Answer 1

Henry Antrim

Easy.

#2.5# #liters# of a #0.08# #molar# solution of #HCI# gives us #mol##es# of #HCl# in the solution

#Molarity#*#Volume# = #mol##es#

#0.08# #(mol)/cancel L# * #2.5 cancel L# = #0.2 mol##es# #HCl#

Now you must convert #mol##es# to #grams#

The mass of HCl in milliliters is 1.01 (g)/(mol) for H and 35 (g)/(mol) for Cl.

#HCl = 1+35=36(g)/(mol)#

#(0.2 cancel mol)/1# * #36 (g)/(cancel mol)# = #color (red) (7.2 g)# #HCl#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Xavier Avery

To calculate the mass of HCl required to prepare a 0.08 molar solution, you can use the formula:

mass = moles × molar mass

First, calculate the number of moles of HCl needed using the formula:

moles = Molarity × Volume

Then, use the molar mass of HCl (which is approximately 36.46 g/mol) to convert moles to grams.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.