How do you calculate the derivative of #d/dx∫sin^2tdt# from 0 to x?

Answer 1
This is direct application of the Fundamental Theorem of Calculus, the derivative of the given definite integral would #sin^2x#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

To calculate the derivative of ( \frac{d}{dx} \int_{0}^{x} \sin^2(t) , dt ), you apply the Fundamental Theorem of Calculus and the Chain Rule. The derivative is equal to the integrand evaluated at the upper limit multiplied by the derivative of the upper limit, which is ( 1 ). So, the derivative is ( \sin^2(x) ).

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7