How do you calculate the derivative for #g(t)= 7/sqrtt#?

Answer 1

Scarlett Allison

You can rewrite the equation #g(t)=7*t^(-1/2)#

Minus because it's under the bar, 1/2 because it's a square root.

Then it's the recipe: one off the power, multiply by the power:

#g'(t)=7*(-1/2)*t^(-1 1/2)=7/(2*t sqrtt#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Evelyn Agard

To calculate the derivative of ( g(t) = \frac{7}{\sqrt{t}} ), you would use the power rule for differentiation. The power rule states that if ( f(x) = x^n ), then ( f'(x) = nx^{n-1} ).

In this case, ( g(t) ) can be rewritten as ( 7t^{-\frac{1}{2}} ). Applying the power rule, the derivative of ( g(t) ) is ( g'(t) = -\frac{7}{2}t^{-\frac{3}{2}} ), which can be further simplified to ( g'(t) = -\frac{7}{2\sqrt{t^3}} ).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.