How do you calculate the amount of heat needed to increase the temperature of 250g of water from 20 C to 56 C? #C_g = 4.8 J/(C-g)#

Answer 1

#=43.2kJ#

  1. Given the data, the formula to use is
    #Q=mCpDeltaT#
    where:
    #m=250g#
    #DeltaT=T_2-T_1=56-20=36^oC#
    #Cp=(4.8J)/(g*C)#
  2. This case, just plug in given data to find the heat needed to raise the temperature of the water as provided in the problem.
    #Q=(250cancel(g))((4.8J)/cancel((g*C)))(36^cancel(oC))#
    #Q=43200J#
    #Q=43.2kJ#
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Answer 2

To calculate the amount of heat needed, use the formula: Q = mcΔT.

Where:

  • Q is the amount of heat needed (in joules)
  • m is the mass of the substance (in grams)
  • c is the specific heat capacity of the substance (in J/(g°C))
  • ΔT is the change in temperature (in °C)

Given:

  • m = 250 g
  • c = 4.8 J/(g°C)
  • ΔT = (56°C - 20°C) = 36°C

Substitute the values into the formula: Q = (250 g) * (4.8 J/(g°C)) * (36°C)

Calculate: Q = 43,200 J

So, the amount of heat needed to increase the temperature of 250g of water from 20°C to 56°C is 43,200 joules.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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