How do you calculate #log_5 (18)#?

Answer 1

#log_5 18=1.7959#

Let #log_nm=x#
then #n^x=m# and taking log to the base #10# on each side
#xlogn=logm# i.e. #x=logm/logn#
i.e. we can write #log_nm=logm/logn#
or #log_5 18=log18/log5=1.2553/0.6990=1.7959#
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Answer 2

To calculate ( \log_5(18) ), you would use the logarithmic property that states ( \log_b(a) = \frac{\log_c(a)}{\log_c(b)} ), where ( c ) is any base. So:

[ \log_5(18) = \frac{\log_{10}(18)}{\log_{10}(5)} ]

Using a calculator, you would first find the base-10 logarithm of 18, then divide it by the base-10 logarithm of 5 to get the result.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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