Home > Precalculus > Common Logs

How do you calculate # log_3 sqrt243#?

Answer 1

Anna Allen

First, use the exponent rule #root(a)(n) = n^(1/a)#

#log_3(243^(1/2))#

Now, use the log rule #loga^n = nloga#

#1/2log_3(243)#

Now, use the log rule #log_an = logn/loga#

#1/2(log243/log3)#

Rewrite 243 in base 3.

#1/2((log3^5)/log3)#

#1/2((5log3)/log3)#

#1/2 xx 5#

#5/2#

Thus, completely simplified, #log_3(sqrt(243)) = 5/2 or 2.5#

Hopefully this helps!

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Trending questions

Not the question you need?

HIX Tutor

Solve ANY homework problem with a smart AI

98% accuracy study help
Covers math, physics, chemistry, biology, and more
Step-by-step, in-depth guides
Readily available 24/7