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How do you calculate concentration from titration?

Answer 1

#M_AV_A# = #M_BV_B#

Assuming you are titrating a strong base (1.0 M NaOH) with a strong acid (10 mL unknown concentration HCl), you will find that it takes 25 mL of NaOH to neutralize the acid.

#M_A# = (#M_BV_B#) / #V_A#

or #M_A# = (1.0M x 25mL) / 10

#M_A# = 2.5M HCl

Because M = moles/L, this is effective.

*Note: If the volumes of the acid and base are expressed in the same unit (mL), there is no need to convert them to liters.

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Answer 2

Cameron Andrews

[ \text{Concentration (M)} = \frac{\text{Moles of solute}}{\text{Volume of solution (L)}} ]

For titration, you can rearrange the formula:

[ \text{Concentration (M)} = \frac{\text{Moles of titrant}}{\text{Volume of titrant (L)}} ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.